实现文件上传的程序源码的PHP源码(页 1) - ASP,PHP,CGI,JSP技术 - 捌玖网络工作室 |网页制作|平面设计|建站交流|代码资料|建站教程|主机域名|asp、php、jsp代码|网站素材

admin 发表于 2007-11-17 08:53

实现文件上传的程序源码的PHP源码

如何实现文件上传 ?[code]
<HTML> z.u&?Tp'j:GK
<HEAD>
<TITLE>文件上传界面</TITLE> ACVy.gwD Y&K
</HEAD> 8e1kg9`'V
<BODY><TABLE><CENTER> &GL m&G E3FC
<? 0GUE.Q"~.X4g
if($UploadAction){1_?\"ZR;Q
$UploadAction=0;
$TimeLimit=60; 'xh`kb3f]
/*设置超时限制时间默认时间为 30s，设置为0时为不限时 */ m*Re ^ZOfU'u4d
set_time_limit($TimeLimit);
If(($Upfile != "none")&&
($Upfile != ""))
{ &V)U&? vQ
$Filepath="d:\web\web\php\test"; //上载文件存放路径
$FileName=$Filepath.$Upfile_name; _$s^0as0r
if($Upfile_size <1024) //上载文件大小
{$FileSize = (string)$Upfile_size . "字节";} %G:B~,M6UfR
elseif($Upfile_size <(1024 * 1024)) L7T+mv2??.XDRU%d
{f#S \l)A
$FileSize = number_format((double)($Upfile_size / 1024), 1) . " KB";
}
else
{
$FileSize = number_format((double)($Upfile_size/(1024*1024)),1)."MB"; Y1x?L,f[j
}
if(!file_exists($FileName))
{
if(copy($Upfile,$FileName))
{unlink($Upfile); S+m)^*V3{
echo "<br><br>\n";
echo "文件 $Upfile_name 已上载成功！";
echo "<br><br>\n";
echo "文件位置：$FileName";l.[C^,s0Rk%l
echo "<br><br>\n";
echo "文件大小：$FileSize";
echo "<br><br>\n";0N/JLk#i$eZ\JO
}
else
{echo "文件 $Upfile_name上载失败！"; }
}
else
{echo "文件 $Upfile_name已经存在！"; } '[&i+NxU
}
else V2[}%['`-t
{echo "你没有选择任何文件上载！"; } T/A{9v)E0qG
set_time_limit(30); //恢复默认超时设置
}
?>
<FORM ENCTYPE = "multipart/form-data" NAME = "SubmitForm" 7f CZ`9R
ACTION = "default.php" METHOD = "POST"> 3f(P2r(O.F{5aYG
<INPUT TYPE = "hidden" NAME = "MAX_FILE_SIZE" VALUE ="1000000">
<INPUT TYPE = "hidden" NAME = "UploadAction" VALUE = "1"> np h\X{
<TR><TD><INPUT NAME = "Upfile" TYPE = "file" SIZE = "30"></TD> ih0ZeG2Z&|U l[
</TR><TR><TD><INPUT NAME = "submit" VALUE = "提交" TYPE = "submit">%f-T Z;PrtWms
<INPUT NAME = "reset" VALUE = "重置" TYPE = "reset"></TD> ${_${$^BfNc
</TR></FORM></CENTER></TABLE>
</BODY>
</HTML>[/code]

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实现文件上传的程序源码的PHP源码