网页制作中页面的加密和破解

网页加密, 网页破解

当你在浏览网页时，看到一个很漂亮的特效，你查看源代码时看到的是一队乱码，那多扫兴呀！根据本人的研究，总结出了三种解密方法，与大家分享！！7 V, i7 V& {: q" \/ s
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方法一：

　　有一种加密的办法是采用javascript的escape()函数，把某些符号、汉字等变成乱码，以达到迷惑人的目的。解密这种代码的办法是采用其反函数加以还原。下面是一个经过加密的例子：
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<HTML>! |' A0 a- H: l! h- s3 P; z
<SCRIPT LANGUAGE="javascript">
var Words ="%3Chtml%3E%3Cbody%20bgcolor%3D%22red%22%3E%3Cp%3E%u8FD9%u662F%u4F8B%u5B50%uFF01%uFF01%uFF1A%uFF09%3C/p%3E%3C/body%3E%3C/html%3E"1 I  N- d4 V4 l  g
var NewWords;  T& N/ l3 a, i+ f) T# V" T; N! X
NewWords = unescape(Words);
document.write(NewWords)
</SCRIPT>8 l0 ~' L. V, ^) a) Y2 {
<BODY>
</BODY>; G6 [. ^8 z, T- W# X* r
</HTML>
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　　这种文件最好解密，一看就明白，关键是unescape()函数起了还原源代码的作用。要想看到加密前的代码是什么样子，可以用下面的办法：+ k3 Q( w5 E0 s1 j

<HTML><SCRIPT LANGUAGE="javascript">/ e7 x! n9 X% x/ f5 a3 X7 i
var Words ="%3Chtml%3E%3Cbody%20bgcolor%3D%22red%22%3E%3Cp%3E%u8FD9%u662F%u4F8B%u5B50%uFF01%uFF01%uFF1A%uFF09%3C/p%3E%3C/body%3E%3C/html%3E"
var NewWords;$ j, C" r& b0 @2 _" v5 _5 W
NewWords = unescape(Words);
NewWords=NewWords.toString();, `, }! a- C1 r6 ~% I1 X8 w6 i
function password(){
document.pw.txtpw.value=NewWords;
}
</SCRIPT>3 o. j; X5 J2 D# n* P
<BODY>
<form name=pw>
<input type=button onclick="password()" value="解密">
<br>
<textarea name="txtpw" cols="100" rows="100"></textarea>; ^( @& G; P9 Z8 z' C0 w
</form>
</BODY>0 k" a5 V& B  X8 G; Z! ^2 A# Z
</HTML>) N* t6 f) z  F! ^" n

方法二：

　　有一个软件叫HTMLEncrypt.exe，它就是把源代码进行加密的软件，这个软件的加密的原理是把字符转换成Unicode代码。下面的例子是一个分帧的页面：
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<html><head><script>
function Carbosoft( s ) { var sRet=""; for(j=0; j< s.length; j++ ){ var n= s.charCodeAt(j); if (n>=8364) {n = 128;} sRet += String.fromCharCode( n - 3 ); } return( sRet ); }- H4 s( w7 l1 Q
var sJsCmds ="" +5 L; h% q( ?- R$ C' h' a) k
"?kwpoA?khdgA?phwd#kwws0htxly@%Frqwhqw0W|sh%#frqwhqw@%wh{w2kwpo>#fkduvhw@lvr0;;8<04%A?wlwohAZHOFRPH?2wlwohA?phwd#qdph@%JHQHUDWRU%#frqwhqw@%Plfurvriw#IurqwSdjh#613%A?phwd#qdph@%Plfurvriw#Wkhph%#frqwhqw@%qrqh/#ghidxow%A?phwd#qdph@%Plfurvriw#Erughu%#frqwhqw@%qrqh/#ghidxow%A?2khdgA?iudphvhw#erughu@%3%#iudpherughu@%3%#urzv@%-/93%A##?iudph#qdph@%pdlq%#vuf@%xs1kwp%#vfuroolqj@%dxwr%A##?iudph#qdph@%rqolqh%#vuf@%grzq1kwp%#vfuroolqj@%qr%#qruhvl}h#wdujhw@%beodqn%A##?qriudphvA##?erg|A##?sAWklv#sdjh#xvhv#iudphv/#exw#|rxu#eurzvhu#grhvq*w#vxssruw#wkhp1#?2sA##?2erg|A##?2qriudphvA?2iudphvhwA?2kwpoA?irqw#froru@%&33333%A?s#doljq@%fhqwhu%A?vpdooA?irqw#idfh@%Wdkrpd%AWklv#iloh#zdv#hqfu|swhg#xvlqj#dq#xquhjlvwhuhg#yhuvlrq#ri#?d#kuhi@%kwws=22fduer{1wkhgqv1qhw2kwpohqfu|sw1kwp%AKWPO#Hqfu|sw#y413?2dA1?2irqwA?2vpdooA?2sA" +: X8 X: s, g/ l2 {; h! e) n3 q
"";- s; ?# \) F( X: g- F
var s= Carbosoft( sJsCmds);4 P3 j! ]9 g$ b: L  \
document.write (s);
</script>- s9 p1 B  g: q
</head><body></body></html>

　　从上面可以看出，浏览器解释这写代码前，进行了还原，从而可以得到破解的方法如下：0 G4 `9 U& m6 R
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<script>$ a1 B- n  o/ y* w' v/ k
function Carbosoft( s ) { var sRet=""; for(j=0; j< s.length; j++ ){ var n= s.charCodeAt(j); if (n>=8364) {n = 128;} sRet += String.fromCharCode( n - 3 ); } return( sRet ); }
var sJsCmds ="" +
"?kwpoA?khdgA?phwd#kwws0htxly@%Frqwhqw0W|sh%#frqwhqw@%wh{w2kwpo>#fkduvhw@lvr0;;8<04%A?wlwohAZHOFRPH?2wlwohA?phwd#qdph@%JHQHUDWRU%#frqwhqw@%Plfurvriw#IurqwSdjh#613%A?phwd#qdph@%Plfurvriw#Wkhph%#frqwhqw@%qrqh/#ghidxow%A?phwd#qdph@%Plfurvriw#Erughu%#frqwhqw@%qrqh/#ghidxow%A?2khdgA?iudphvhw#erughu@%3%#iudpherughu@%3%#urzv@%-/93%A##?iudph#qdph@%pdlq%#vuf@%xs1kwp%#vfuroolqj@%dxwr%A##?iudph#qdph@%rqolqh%#vuf@%grzq1kwp%#vfuroolqj@%qr%#qruhvl}h#wdujhw@%beodqn%A##?qriudphvA##?erg|A##?sAWklv#sdjh#xvhv#iudphv/#exw#|rxu#eurzvhu#grhvq*w#vxssruw#wkhp1#?2sA##?2erg|A##?2qriudphvA?2iudphvhwA?2kwpoA?irqw#froru@%&33333%A?s#doljq@%fhqwhu%A?vpdooA?irqw#idfh@%Wdkrpd%AWklv#iloh#zdv#hqfu|swhg#xvlqj#dq#xquhjlvwhuhg#yhuvlrq#ri#?d#kuhi@%kwws=22fduer{1wkhgqv1qhw2kwpohqfu|sw1kwp%AKWPO#Hqfu|sw#y413?2dA1?2irqwA?2vpdooA?2sA" +3 y& z0 a6 G* f$ S* a
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var s= Carbosoft( sJsCmds);3 m3 Q' w4 G6 N$ m3 Z/ u
</script>+ ]4 s, b2 l. i3 ]% j; |& c  L
<form name=qq>1 U: o; O2 M4 P6 v) e- ^5 u/ r. ?
<textarea name=ww cols=100 rows=10></textarea>5 L6 o0 E9 _) i- h5 }; P
<input onclick='ww.value=s' type=button value="解密">; }3 P% A( n0 s0 A& b: y( w( n, D
</form>0 r5 d& T, ?9 i+ w0 f
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方法三：

　　有一种加密方法是每行单独加密，还原起来比较复杂。看一个加密过的原文：  i: [6 Y) t- l! [. [" \$ A. v2 r0 O
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<HTML>
<BODY>
<SCRIPT LANGUAGE="javascript">
function Decode() {+ J0 X7 u. x$ L7 Y) R9 f% M
d("FrfmnD");d("FruyvDFgwhqjfWnyeseysuEXpydy%whqjf~J~XWghwEXfkjJpgXDFIgwhqjfD");d("FmufyWrffjKuieqdEX?klfulfK$ajuXWwklfulfEXfubfIrfmnGWwryhgufEsx}{~}XD");d("FfqfnuDejFIfqfnuD");d("FIruyvD");d("FxkvaD");d("FIxkvaD");d("FIrfmnD");d("W");return 0;}! E( f% V4 U2 B( P+ T) |+ v4 t8 n
</SCRIPT>' S6 G9 t4 W0 q7 M9 M0 d4 i9 x
<SCRIPT LANGUAGE="javascript">, w* l! l" \" N. k
function d (enc) {document.write(codeIt(key,enc));}, h, n+ T& D' Z+ @5 ~3 a" z& i% G% P
var key = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz!\"\ \|#$%&\'()*+,-.\/:;<=>?@[\\]^_\t\`{}~\n";function codeIt (mC, eS) {var wTG, mcH = mC.length / 2, nS = "", dv;for (var x = 0; x < eS.length; x++) { wTG = mC.indexOf(eS.charAt(x));if (wTG > mcH) {dv = wTG - mcH; nS = nS + mC.charAt(48 - dv);}else {dv = mcH - wTG;nS = nS + mC.charAt(48 + dv);}}return nS;}
</SCRIPT>. w/ L1 v2 O' B7 w1 M
<SCRIPT LANGUAGE="javascript">
Decode();
</SCRIPT>
</BODY>% w: n2 `0 i/ J3 ~- }1 @1 M' @
</HTML>
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　　还原的时候，也必须每行单独解密，用下面的方法可以看到源代码：$ M9 n8 v& E- a- P6 ]
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<HTML>
<BODY>  ?' `# m. W/ k
<SCRIPT LANGUAGE="javascript">
function Decode() {8 j2 X' {- Y- R9 [5 V, T
d("FrfmnD");d("FruyvDFgwhqjfWnyeseysuEXpydy%whqjf~J~XWghwEXfkjJpgXDFIgwhqjfD");d("FmufyWrffjKuieqdEX?klfulfK$ajuXWwklfulfEXfubfIrfmnGWwryhgufEsx}{~}XD");d("FfqfnuDejFIfqfnuD");d("FIruyvD");d("FxkvaD");d("FIxkvaD");d("FIrfmnD");d("W");return 0;}4 d* W, e' U0 L, R# ~# M  j+ K
</SCRIPT>. b4 X; f$ l: x' v3 X0 Z
<SCRIPT LANGUAGE="javascript">5 z/ [( z  O6 r( t( Y% y& P
function d (enc) {alert(codeIt(key,enc));}2 @0 k- c( N, |$ Z5 w) J. A
var key = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz!\"\ \|#$%&\'()*+,-.\/:;<=>?@[\\]^_\t\`{}~\n";function codeIt (mC, eS) {var wTG, mcH = mC.length / 2, nS = "", dv;for (var x = 0; x < eS.length; x++) { wTG = mC.indexOf(eS.charAt(x));if (wTG > mcH) {dv = wTG - mcH; nS = nS + mC.charAt(48 - dv);}else {dv = mcH - wTG;nS = nS + mC.charAt(48 + dv);}}return nS;}5 R8 x! J0 H2 C& q8 u
</SCRIPT>) v' S5 R$ K7 R/ |: i% N% @2 ~
<SCRIPT LANGUAGE="javascript">. {) L$ B% U/ K
Decode();
</SCRIPT>3 N6 Q1 R. z  u) N: {0 X
</BODY>
</HTML>
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　　哈哈！！:=)是不是很精彩！！

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